Results 1 to 3 of 3

Thread: This Weeks Video Release: How To Identify Lens Materials

  1. #1
    Master OptiBoarder
    Join Date
    Sep 2008
    Location
    Anderson SC
    Occupation
    Dispensing Optician
    Posts
    755

    This Weeks Video Release: How To Identify Lens Materials


  2. #2
    Master OptiBoarder optical24/7's Avatar
    Join Date
    May 2006
    Location
    Down on the Farm
    Occupation
    Dispensing Optician
    Posts
    5,826
    John, another great video! You can also use a lens clock and lensometer to tell the material. From an article I wrote for a state association news letter a number of years ago...

    Determining Index of Refraction

    How do we determine the index of refraction of an unknown lens material? Polycarbonate is easy to tell, we all use the “pling” test, verifying the distinct sound they make dropped on a table top (they sound like a poker chip).

    But how do we tell CR39 from a mid-index, or 1.60 from 1.67? There’s a neat mathematical trick to get a close approximation. The formula is..

    N = .53 X ( TP/CP ) + 1

    N = Index Approximation
    TP = True Power
    CP = Clock Power

    True power is what you read in your lensometer. Clock power is your power calculation using a standard lens clock. Let’s go over using a lens clock quickly. To get a “clock power” take your standard lens clock and read the front surface curvature. Next clock the back curve ( for this calculation use the flattest back curve if the lens has cylinder). For a minus lens, subtract the front curve from the back curve to get the clock power. ( For plus lenses subtract the back from the front for the clock power).

    Some examples pulled from my stock lens inventory;

    Lens #1 Clocks +2.50 front/-5.75 back. -5.75 - +2.50 = -3.25. Lens reads
    -3.75 in the lensometer so;
    .53 X ( 3.75/3.25 ) + 1 = 1.611 This lens is in fact a 1.60

    Lens #2 Clocks +1.25 front/-7.75 back. -7.75 - +1.25 = -6.50. Lens reads
    -8.25 in the lensometer so;
    .53 X ( 8.25/6.50 ) + 1 = 1.672 This lens is in fact a 1.67

    Keep in mind this is an approximation formula. Aspheric lenses can affect your answers because of changing curvature. But this can be a useful formula when trying to determine the index of an unknown lens.

  3. #3
    Master OptiBoarder
    Join Date
    Sep 2008
    Location
    Anderson SC
    Occupation
    Dispensing Optician
    Posts
    755
    I'll post a link out to this from our FB page.

    Thanks!

Thread Information

Users Browsing this Thread

There are currently 1 users browsing this thread. (0 members and 1 guests)

Similar Threads

  1. This Weeks Video Release: How To Pass The ABO
    By John@OWDC in forum General Optics and Eyecare Discussion Forum
    Replies: 3
    Last Post: 02-08-2018, 04:13 PM
  2. This Weeks Video Release: Part III (well IV) of IV on The Nominal Lens Formula
    By John@OWDC in forum General Optics and Eyecare Discussion Forum
    Replies: 0
    Last Post: 02-01-2018, 08:04 AM
  3. This Weeks Video Release: Part IV (III) of IV The Nominal Lens Formula
    By John@OWDC in forum General Optics and Eyecare Discussion Forum
    Replies: 0
    Last Post: 01-25-2018, 07:23 AM
  4. This Weeks Video Release: Part I of IV The Nominal Lens Formula
    By John@OWDC in forum General Optics and Eyecare Discussion Forum
    Replies: 8
    Last Post: 01-12-2018, 10:29 AM
  5. This Weeks Video Release: Effective Power & Lens Tilt
    By John@OWDC in forum General Optics and Eyecare Discussion Forum
    Replies: 0
    Last Post: 09-28-2017, 07:09 AM

Bookmarks

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •