Kwill212
please give a more detailed explanation of your solution. The cylinder on a lens has no power it only represents the difference between the principal meridians in this case +5.00 and 0.00
Take the two parts separately. 5.00 sphere decentered in 10 mm gives you 5D BI prism. Then do the cylinder. Prism created by decentering a cylinder requires a little trig or graph paper. A -5.00...
Hi Lensman, thank you for your response. To be sure, I assumed the OptiCampus calculation was correct. In years past, I would have picked up the phone and called Darryl. :(
Before I decided to post this, I searched through the web and this site but didn't find exactly what I am looking for. I would like to know if somebody can help me with the center thickness formula...
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Kwill212 please give a more detailed explanation...
Kwill212
Lensman11 01-16-2021, 03:34 PMplease give a more detailed explanation of your solution. The cylinder on a lens has no power it only represents the difference between the principal meridians in this case +5.00 and 0.00