Darryl,

I know you enjoy the math and I recently got a question about lenticulars from an optician and thought I'd share it.

The type of lenticular you are asking about cannot be done using
traditional processing techniques, if you needed to make a minus
lenticular or myodisc that can be done and is fairly easy. First you
would need to determine your minimum blank size of the lens

mbs = minimum blank size
dec = decentration
DPD = distance PD
ED = effective diameter

mbs = ED + 2*dec + 1mm

Now that we have our minimum bank size we can determine the saggital
height of the lens using the front curve and minimum blank size.

F1 = front curve in diopters
n = material index

sag(F1)@mbs = [F1*(mbs/2)^2]/[2000*(n-1)]

Now using the back curve and the optical zone we need to find out
where the optical zone intersects the peripheral curve.

F2 = back curve in diopters
oz = optic zone

sag(F2)@oz = [F2*(oz/2)^2]/[2000*(n-1)]

Now we need to know the diference between the plate height of the
front curve and the sag of the back curve.

diff = difference
ct = center thickness

diff = sag(F1)@mbs + ct - sag(F2)@oz

Now this difference will help us detremine the peripheral curve, for
the peripheral curve to be correct the differnce between the
peripheral curve sag at the minimum blank size minus the peripheral
curve at the optical zone size will be equal to the difference.

F3 = peripheral curve
sag(F3)@mbs = [F3*(mbs/2)^2]/[2000*(n-1)]
sag(F3)@oz = [F3*(oz/2)^2]/[2000*(n-1)]

diff = sag(F3)@mbs - sag(F3)@oz

If we substitute out the forumulas above and simplify we get:

diff = sag(F1)@mbs + ct - sag(F2)@oz
diff = [F1*(mbs/2)^2]/[2000*(n-1)] + ct + [F2*(oz/2)^2]/[2000*(n-1)]

diff = sag(F3)@mbs - sag(F3)@oz
diff = [F3*(mbs/2)^2]/[2000*(n-1)] - [F3*(oz/2)^2]/[2000*(n-1)]

Now we set them equal to each other:

[F3*(mbs/2)^2]/[2000*(n-1)] - [F3*(oz/2)^2]/[2000*(n-1)] =
[F1*(mbs/2)^2]/[2000*(n-1)] + ct + [F2*(oz/2)^2]/[2000*(n-1)]

Now we simplify, start by multiplying both sides by 2000*(n-1) which
woudl give us:

[F3*(mbs/2)^2] - [F3*(oz/2)^2] = [F1*(mbs/2)^2] + [ct*2000*(n-1)] + [F2*(oz/2)^2]
F3*[(mbs/2)^2 - (oz/2)^2] = [F1*(mbs/2)^2] + [ct*2000*(n-1)] + [F2*(oz/2)^2]
F3 = { [F1*(mbs/2)^2] + [ct*2000*(n-1)] + [F2*(oz/2)^2] } / [(mbs/2)^2 - (oz/2)^2]

So now we know what our peripheral curve is so we need to know what
thickness to cut the first cut our peripherl curve onto.

pt = peripheral curve thickness

pt = sag(F1)@mbs + ct - sag(F3)@mbs

So then your steps would be to:
1.) generate the F3 curve at a thickness of pt onto your blank and run
it through the finer and polisher
2.) tape the back surface with surface saver tape
3.) cut the F2 curve at a thickness of ct onto your blank and run it
through the finer and polisher

At no point should the lenses be deblocked they should remain on the
blocks through the entire processing steps then removed at the end.