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Thread: Cylinder in an Oblique meridian

  1. #1
    Rising Star
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    Confused Cylinder in an Oblique meridian

    I posted this is the Optics section, but this seems like a more appropriate place to ask this question:


    Does anyone know a more exact way of calculating the power of cylinder in an oblique meridian other than the sine-squared approximation method: Fa = Fcyl [sin(a)]^2 ? Or does the torsional effect prevent from getting an exact power? ... or can we account for torsional effect? (or is it not substantial enough to find this?)
    "The Drizzle", ABOC-AC ... word to your mother.

  2. #2
    Carl Zeiss Vision, Americas OptiBoard Corporate Sponsor Darryl Meister's Avatar
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    Cylinder in an Oblique meridian.

    Best regards,
    Darryl
    Darryl J. Meister, ABOM

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