I posted this is the Optics section, but this seems like a more appropriate place to ask this question:
Does anyone know a more exact way of calculating the power of cylinder in an oblique meridian other than the sine-squared approximation method: Fa = Fcyl [sin(a)]^2 ? Or does the torsional effect prevent from getting an exact power? ... or can we account for torsional effect? (or is it not substantial enough to find this?)![]()




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