I just want to make sure I understand how this will work, or better yet find out if it will work. Here goes CR39 st28
RX = OD +1.75 -3.50 X 093 with 4.50 BU
OS -1.50 -3.50 x090 with 4.50 BD
3.25 add eliminates Reverse unless Dr ok's 3.00 or 3.50
A=53.0 B= 38.0 seg height = 15.0 OC 4 above
Reading drop of 9mm = 2.92 BU OS
Will the BD at distance in the OS cancel the BU at near for
the slab-off????? I would think they are two seperate properties of the lense, at 4mm above the seg the patient will have 4.50 BD but I'm not sure I understand what effect the distant prism will have on the near prism.
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