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Thread: Distance PD vs Near Pd

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    OptiBoard Professional Leighlee's Avatar
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    Confused Distance PD vs Near Pd

    Hi,

    Ok in the olden days if a distance PD was 67, you would take 3 off, or substract 3 to get a near PD of 64. Is that still the rule? Remember, I am a returning optician after a +10 year break. Thanks all!!:hammer:

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    Manuf. Lens Surface Treatments OptiBoard Gold Supporter
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    Redhot Jumper Near PD.........................

    Quote Originally Posted by Leighlee View Post
    Hi,

    Ok in the olden days if a distance PD was 67, you would take 3 off, or substract 3 to get a near PD of 64. Is that still the rule? Remember, I am a returning optician after a +10 year break. Thanks all!!:hammer:
    That is still the rule for near PD at normal reading distsnace. However it can change if the Rx is for very clos up or further away. Pure mathematics.
    Chris Ryser
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    Quote Originally Posted by Leighlee View Post
    Hi,

    Ok in the olden days if a distance PD was 67, you would take 3 off, or substract 3 to get a near PD of 64. Is that still the rule? Remember, I am a returning optician after a +10 year break. Thanks all!!:hammer:
    People with narrow PD's converge less, wide PD's more, so 55/53, 60/57, 70/66 - PAL's usually allow 5mm inset from MRP to reading - if any Kentucky windage necessary, remember base in is better than base out for reading

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    Optimentor Diane's Avatar
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    Take each independently

    Each should be taken independently. Every person is different. With a CRP, it's easy enough to simply set the distance and take the correct measurement. If you do it using a penlight and a ruler, simply have them focus at the appropriate near distance.

    I've never taught take the distance and subtract 3 mm.

    Diane
    Anything worth doing is worth doing well.

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    I also take one using CRP if fitting sv or prog. If they are wearing flat-tops, I use what finefocus said above. People do not like it when one bif looks different than the other(more inset). "My old ones ain't that way". Me: "well mr. W, your left eye sits about 2mm farthur out than your right and these are optically perfect" Mr. W "my old ones ain't that way" Repeat above about 4 times, then re-do using the above way to get a near PD.

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    Enjoying the education drk's Avatar
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    HAH! Scooped Chilinguerian, who probaby has this tatooed on his ****...

    You can also measure a Distance PD and calculate the Near PD for any reading distance using:
    Near PD = [Distance PD mm * (10 * Reading Distance cm)] / [(10 * Reading Distance cm) + 27]
    where the Reading Distance is given in centimeters and the PDs are in millimeters.
    __________________

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    That's also assuming normal convergence though. I usually just take off 3, unless they have an odd distance PD, then I take both.

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    ATO Member OptiBoard Bronze Supporter HarryChiling's Avatar
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    Quote Originally Posted by drk View Post
    You can also measure a Distance PD and calculate the Near PD for any reading distance using:
    Near PD = [Distance PD mm * (10 * Reading Distance cm)] / [(10 * Reading Distance cm) + 27]
    where the Reading Distance is given in centimeters and the PDs are in millimeters.
    __________________
    LOL, I use a table but I know the formula well.

    NPD / WD = DPD / (WD + CTR)

    Then you cross multiply to get the form of the equation you have there.

    Also the seperate sides of the equation give you the angle the eye deviates to view the object. Here's a graphic example. Beat that Drk. ;)
    Attached Thumbnails Attached Thumbnails Click image for larger version. 

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    Enjoying the education drk's Avatar
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    I got....nothing. :cheers:

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    ATO Member OptiBoard Bronze Supporter HarryChiling's Avatar
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    Quote Originally Posted by drk View Post
    I got....nothing. :cheers:
    LOL, you had it. Feel free to download and use the image GPL.

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